Class 9 › Mathematics › Chapter
Coordinates (The Cartesian Plane)
Axes, origin, ordered pairs, quadrants, distance formula, reflection, midpoint and trisection points, and how coordinates are used to test geometric properties.
1-D (number line)
One number locates a point. Used for integers, rationals and decimals.
2-D (plane)
Two numbers locate a point, using two perpendicular number lines. This is the Cartesian coordinate system.
- Key idea (Descartes): every point in a plane is fixed by exactly two numbers, its distances from two perpendicular axes.
- Why it matters: shapes and curves can be described by algebra and equations, and equations can be seen as shapes, which joins geometry and algebra.
- Role of negative numbers: the origin is zero and the negative axes represent values less than zero. Without negatives only one quarter of the plane (Quadrant I) could be located.
x-axis
The horizontal number line.
y-axis
The vertical number line.
Origin $O$
The point where the axes intersect (cross at $90^\circ$). Its coordinates are $(0, 0)$.
- Equal units (same scale) are marked on both axes, measured from $O$.
- Positive: to the right of $O$ along the x-axis, and upwards from $O$ along the y-axis.
- Negative: to the left of $O$ along the x-axis, and downwards from $O$ along the y-axis.
"Axes" is the plural of "axis". Position of the origin is a convention; for example, computer screens place the origin at the bottom-left corner.
• x-coordinate (abscissa) = perpendicular distance of $P$ from the y-axis, measured along the x-axis.
• y-coordinate (ordinate) = perpendicular distance of $P$ from the x-axis, measured along the y-axis.
- $(x, y)$ is an ordered pair: the x-coordinate is always written first.
- Two ordered pairs are equal only if both corresponding coordinates are equal.
- $(x, y) = (y, x)$ if and only if $x = y$. If $x \neq y$, then $(x, y) \neq (y, x)$ (they are different points).
- Each point has exactly one ordered pair, and each ordered pair marks exactly one point.
$(x, 0)$
y-coordinate is $0$. If $x \gt 0$ the point is right of $O$; if $x \lt 0$, left of $O$.
$(0, y)$
x-coordinate is $0$. If $y \gt 0$ the point is above $O$; if $y \lt 0$, below $O$.
$(0, 0)$
Both coordinates are $0$. It is the only point lying on both axes.
$x = k$
Every point on a vertical line has the same x-coordinate $k$: $(k, y)$.
$y = k$
Every point on a horizontal line has the same y-coordinate $k$: $(x, k)$.
The plane in which the axes lie is called the Cartesian plane, coordinate plane or xy-plane. The two axes divide it into four parts called quadrants, numbered I to IV anticlockwise, starting from the top right.
| Quadrant | x-coordinate | y-coordinate | Location |
|---|---|---|---|
| I | positive | positive | Top right |
| II | negative | positive | Top left |
| III | negative | negative | Bottom left |
| IV | positive | negative | Bottom right |
Horizontal segment (same $y$)
For points $(x_1, y)$ and $(x_2, y)$.
Vertical segment (same $x$)
For points $(x, y_1)$ and $(x, y_2)$.
- The absolute value $|\cdot|$ keeps the distance positive, so the order of subtraction does not matter.
- This applies whether the points lie on an axis or on any line parallel to an axis.
When the segment joining two points is not parallel to either axis, we form a right-angled triangle and apply the Baudhāyana–Pythagoras Theorem (hypotenuse$^2$ = sum of squares of the other two sides).
- Procedure: subtract the x-coordinates, subtract the y-coordinates, square both, add, then take the square root.
- Sign does not matter: squaring removes any negative sign, so the formula works for points in any quadrant and the order of the two points can be swapped.
- Distance is never negative, and $d = 0$ only when the two points coincide.
- If the segment is parallel to an axis, the formula reduces to $|x_2 - x_1|$ or $|y_2 - y_1|$.
The mirror image of a point is found by treating an axis as a mirror. A point and its image are at the same perpendicular distance from the mirror axis, on opposite sides.
In the y-axis
The x-coordinate changes sign.
In the x-axis
The y-coordinate changes sign.
• Lengths are preserved: the sides of a figure and its image are equal, so shape and size stay the same (verified with the distance formula).
• What changes: the position of the figure and the sign of one coordinate.
• Points on the mirror axis are their own images.
• Two points that are mirror images in an axis share one coordinate and have opposite values of the other.
If $M$ is the midpoint of segment $ST$ with $S(x_1, y_1)$ and $T(x_2, y_2)$, each coordinate of $M$ is the average of the corresponding coordinates of $S$ and $T$.
- Test for a midpoint: $M$ is the midpoint of $ST$ only if both averages match $M$'s coordinates.
- Finding an endpoint: if $M(m_1, m_2)$ and $S(x_1, y_1)$ are known, the other end is $T = (2m_1 - x_1, \; 2m_2 - y_1)$.
- Triangle from midpoints: if $D, E, F$ are the midpoints of $BC, CA, AB$, then $A = E + F - D$, $B = D + F - E$, $C = D + E - F$ (coordinate-wise).
The points $P$ and $Q$ that divide $AB$ into three equal parts ($P$ nearer to $A$, $Q$ nearer to $B$) for $A(x_1, y_1)$ and $B(x_2, y_2)$:
- Idea: $P$ is $\tfrac13$ of the way from $A$ to $B$, i.e. $P = A + \tfrac13(B - A)$, and $Q$ is $\tfrac23$ of the way, i.e. $Q = A + \tfrac23(B - A)$.
- Equivalent method: $Q$ is the midpoint of $PB$ and $P$ is the midpoint of $AQ$.
- Ratio form: $AP : PQ : QB = 1 : 1 : 1$.
Three points on one line
Find the three distances. The points are collinear when the largest distance equals the sum of the other two. No plotting is needed.
Type of triangle
Compare side lengths: two equal means isosceles, all three equal means equilateral. If $a^2 + b^2 = c^2$ for the sides, it is right-angled.
Square / Rectangle
Square: four equal sides and equal diagonals; area = side$^2$. Rectangle: opposite sides equal and diagonals equal.
Position of a point
For radius $r$: $x^2 + y^2 = r^2$ means on the circle, $\lt r^2$ means inside, $\gt r^2$ means outside.
Do they intersect?
With centre distance $d$ and radii $r_1, r_2$: they intersect if $|r_1 - r_2| \lt d \lt r_1 + r_2$; touch if $d = r_1 + r_2$ or $d = |r_1 - r_2|$.
Fits inside a region?
A circle of radius $r$ and centre $(a, b)$ lies inside a rectangle if $a \pm r$ and $b \pm r$ stay within the rectangle's limits.
Parallel & perpendicular sides
Same y-coordinates: side parallel to the x-axis. Same x-coordinates: parallel to the y-axis. These two types of sides are perpendicular.
| Concept | Result |
|---|---|
| Origin | $(0, 0)$ |
| Point on x-axis / y-axis | $(x, 0)$ / $(0, y)$ |
| Quadrant signs | I $(+,+)$, II $(-,+)$, III $(-,-)$, IV $(+,-)$ |
| $(x, y) = (y, x)$ | only when $x = y$ |
| Distance along an axis direction | $|x_2 - x_1|$ or $|y_2 - y_1|$ |
| Distance formula | $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ |
| Distance from origin | $\sqrt{x^2 + y^2}$ |
| Reflection in y-axis / x-axis | $(-x, y)$ / $(x, -y)$ |
| Midpoint | $\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)$ |
| Trisection points | $\left(\frac{2x_1 + x_2}{3}, \frac{2y_1 + y_2}{3}\right)$ and $\left(\frac{x_1 + 2x_2}{3}, \frac{y_1 + 2y_2}{3}\right)$ |
• Writing $(y, x)$ instead of $(x, y)$.
• Treating a point on an axis as lying in a quadrant.
• Mishandling signs: $(-a)^2 = a^2$, not $-a^2$.
• Forgetting the final square root in the distance formula.